5x^2-19x+50=0

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Solution for 5x^2-19x+50=0 equation:


Simplifying
5x2 + -19x + 50 = 0

Reorder the terms:
50 + -19x + 5x2 = 0

Solving
50 + -19x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
10 + -3.8x + x2 = 0

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -3.8x + -10 + x2 = 0 + -10

Reorder the terms:
10 + -10 + -3.8x + x2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -3.8x + x2 = 0 + -10
-3.8x + x2 = 0 + -10

Combine like terms: 0 + -10 = -10
-3.8x + x2 = -10

The x term is -3.8x.  Take half its coefficient (-1.9).
Square it (3.61) and add it to both sides.

Add '3.61' to each side of the equation.
-3.8x + 3.61 + x2 = -10 + 3.61

Reorder the terms:
3.61 + -3.8x + x2 = -10 + 3.61

Combine like terms: -10 + 3.61 = -6.39
3.61 + -3.8x + x2 = -6.39

Factor a perfect square on the left side:
(x + -1.9)(x + -1.9) = -6.39

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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